Question
Factor polynomial $$ 25x^{4}-121y^{2} $$
Answer
$$ 25x^{4}-121y^{2} = (5x^{2}+11y)(5x^{2}-11y) $$
Explanation
Rewrite $ 25x^4-121y^2 $ as:
$$ \color{blue}{ 25x^4-121y^2 = (5x^2)^2 - (11y)^2 } $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 5x^2 $ and $ II = 11y $ , we have:
$$ 25x^4-121y^2 = (5x^2)^2 - (11y)^2 = ( 5x^2-11y ) ( 5x^2+11y ) $$This page was created using
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