Question
Factor polynomial $$ 250c^{4}-432cd^{3} $$
Answer
$$ 250c^{4}-432cd^{3} = 2c(5c-6d)(25c^{2}+30cd+36d^{2}) $$
Explanation
Step 1 :
Factor out common factor $ \color{blue}{ 2c } $:
$$ 250c^4-432cd^3 = 2c ( 125c^3-216d^3 ) $$Step 2 :
To factor $ 125c^{3}-216d^{3} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = 5c $ and $ II = 6d $ , we have:
$$ 125c^{3}-216d^{3} = ( 5c-6d ) ( 25c^{2}+30cd+36d^{2} ) $$This page was created using
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