Rewrite $ -9x^{2}+25 $ as:
$$ -9x^{2}+25 = 25 -9x^2 = (5)^2 - (3x)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 5 $ and $ II = 3x $ , we have:
$$ -9x^{2}+25 = (5)^2 - (3x)^2 = ( -3x+5 ) ( 3x+5 ) $$