Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 22 }$ by the constant term $\color{blue}{c = -35} $.
$$ a \cdot c = -770 $$Step 3: Find out two numbers that multiply to $ a \cdot c = -770 $ and add to $ b = 67 $.
Step 4: All pairs of numbers with a product of $ -770 $ are:
| PRODUCT = -770 | |
| -1 770 | 1 -770 |
| -2 385 | 2 -385 |
| -5 154 | 5 -154 |
| -7 110 | 7 -110 |
| -10 77 | 10 -77 |
| -11 70 | 11 -70 |
| -14 55 | 14 -55 |
| -22 35 | 22 -35 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 67 }$
| PRODUCT = -770 and SUM = 67 | |
| -1 770 | 1 -770 |
| -2 385 | 2 -385 |
| -5 154 | 5 -154 |
| -7 110 | 7 -110 |
| -10 77 | 10 -77 |
| -11 70 | 11 -70 |
| -14 55 | 14 -55 |
| -22 35 | 22 -35 |
Step 6: Replace middle term $ 67 x $ with $ 77x-10x $:
$$ 22x^{2}+67x-35 = 22x^{2}+77x-10x-35 $$Step 7: Apply factoring by grouping. Factor $ 11x $ out of the first two terms and $ -5 $ out of the last two terms.
$$ 22x^{2}+77x-10x-35 = 11x\left(2x+7\right) -5\left(2x+7\right) = \left(11x-5\right) \left(2x+7\right) $$