Step 1 :
After factoring out $ 6 $ we have:
$$ 216v^{2}-294 = 6 ( 36v^{2}-49 ) $$Step 2 :
Rewrite $ 36v^{2}-49 $ as:
$$ 36v^{2}-49 = (6v)^2 - (7)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = 6v $ and $ II = 7 $ , we have:
$$ 36v^{2}-49 = (6v)^2 - (7)^2 = ( 6v-7 ) ( 6v+7 ) $$