Question
Factor polynomial $$ 20y^{3}-10y^{2}+6y-3 $$
Answer
$$ 20y^{3}-10y^{2}+6y-3 = ( 10y^{2}+3 )( 2y-1 ) $$
Explanation
To factor $ 20y^{3}-10y^{2}+6y-3 $ we can use factoring by grouping:
Group $ \color{blue}{ 20x^{3} }$ with $ \color{blue}{ -10x^{2} }$ and $ \color{red}{ 6x }$ with $ \color{red}{ -3 }$ then factor each group.
$$ \begin{aligned} 20y^{3}-10y^{2}+6y-3 = ( \color{blue}{ 20x^{3}-10x^{2} } ) + ( \color{red}{ 6x-3 }) &= \\ &= \color{blue}{ 10x^{2}( 2x-1 )} + \color{red}{ 3( 2x-1 ) } = \\ &= (10x^{2}+3)(2x-1) \end{aligned} $$This page was created using
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