Step 1 :
After factoring out $ 10 $ we have:
$$ 20n^{2}-80n-70 = 10 ( 2n^{2}-8n-7 ) $$Step 2 :
Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 3: Multiply the leading coefficient $\color{blue}{ a = 2 }$ by the constant term $\color{blue}{c = -7} $.
$$ a \cdot c = -14 $$Step 4: Find out two numbers that multiply to $ a \cdot c = -14 $ and add to $ b = -8 $.
Step 5: All pairs of numbers with a product of $ -14 $ are:
| PRODUCT = -14 | |
| -1 14 | 1 -14 |
| -2 7 | 2 -7 |
Step 6: Find out which factor pair sums up to $\color{blue}{ b = -8 }$
Step 7: Because none of these pairs will give us a sum of $ \color{blue}{ -8 }$, we conclude the polynomial cannot be factored.