Question
Factor polynomial $$ 16a^{2}-88ab+121b^{2} $$
Answer
$$ 16a^{2}-88ab+121b^{2} = (4a-11b)(4a-11b) $$
Explanation
Note that the polynomial $ 16a^2-88ab+121b^2 $ is a perfect square trinomial, so we will use the following formula.
$$ A^2 - 2AB + B^2 = (A - B)^2 $$In this example we have $ \color{blue}{ A = 4a } $ and $ \color{red}{ B = 11b } $ so,
$$ 16a^2-88ab+121b^2 = ( \color{blue}{ 4a } - \color{red}{ 11b } )^2 $$This page was created using
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