Question
Factor polynomial $$ 12a^{2}-15ab-8a+10b $$
Answer
$$ 12a^{2}-15ab-8a+10b = (3a-2)(4a-5b) $$
Explanation
To factor $ 12a^2-15ab-8a+10b $ we can use factoring by grouping.
Group $ \color{blue}{ 12a^2 }$ with $ \color{blue}{ -15ab }$ and $ \color{red}{ -8a }$ with $ \color{red}{ 10b }$ then factor each group.
$$ \begin{aligned} 12a^2-15ab-8a+10b &= ( \color{blue}{ 12a^2-15ab } ) + ( \color{red}{ -8a+10b }) = \\ &= \color{blue}{ 3a( 4a-5b )} \color{red}{ -2( 4a-5b ) } = \\ &= (3a-2)(4a-5b) \end{aligned} $$This page was created using
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