Question
Factor polynomial $$ 125a^{3}+27b^{9} $$
Answer
$$ 125a^{3}+27b^{9} = (5a+3b^{3})(25a^{2}-15ab^{3}+9b^{6}) $$
Explanation
To factor $ 125a^{3}+27b^{9} $ we can use sum of cubes formula:
$$ I^3 + II^3 = (I + II) (I^2 - I \cdot II + II^2)$$After putting $ I = 5a $ and $ II = 3b^3 $ , we have:
$$ 125a^{3}+27b^{9} = ( 5a+3b^{3} ) ( 25a^{2}-15ab^{3}+9b^{6} ) $$This page was created using
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