It seems that $ 10x^{2}-8x-7 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 10 }$ by the constant term $\color{blue}{c = -7} $.
$$ a \cdot c = -70 $$Step 3: Find out two numbers that multiply to $ a \cdot c = -70 $ and add to $ b = -8 $.
Step 4: All pairs of numbers with a product of $ -70 $ are:
| PRODUCT = -70 | |
| -1 70 | 1 -70 |
| -2 35 | 2 -35 |
| -5 14 | 5 -14 |
| -7 10 | 7 -10 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = -8 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ -8 }$, we conclude the polynomial cannot be factored.