Question
Factor polynomial $$ 10u^{3}+4u^{2}-15u-6 $$
Answer
$$ 10u^{3}+4u^{2}-15u-6 = ( 2u^{2}-3 )( 5u+2 ) $$
Explanation
To factor $ 10u^{3}+4u^{2}-15u-6 $ we can use factoring by grouping:
Group $ \color{blue}{ 10x^{3} }$ with $ \color{blue}{ 4x^{2} }$ and $ \color{red}{ -15x }$ with $ \color{red}{ -6 }$ then factor each group.
$$ \begin{aligned} 10u^{3}+4u^{2}-15u-6 = ( \color{blue}{ 10x^{3}+4x^{2} } ) + ( \color{red}{ -15x-6 }) &= \\ &= \color{blue}{ 2x^{2}( 5x+2 )} + \color{red}{ -3( 5x+2 ) } = \\ &= (2x^{2}-3)(5x+2) \end{aligned} $$This page was created using
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