It seems that $ -25x^{2}-196x+36 $ cannot be factored out.
Step 1 :
After factoring out $ -1 $ we have:
$$ -25x^{2}-196x+36 = - ~ ( 25x^{2}+196x-36 ) $$Step 2 :
Step 2: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 3: Multiply the leading coefficient $\color{blue}{ a = 25 }$ by the constant term $\color{blue}{c = -36} $.
$$ a \cdot c = -900 $$Step 4: Find out two numbers that multiply to $ a \cdot c = -900 $ and add to $ b = 196 $.
Step 5: All pairs of numbers with a product of $ -900 $ are:
| PRODUCT = -900 | |
| -1 900 | 1 -900 |
| -2 450 | 2 -450 |
| -3 300 | 3 -300 |
| -4 225 | 4 -225 |
| -5 180 | 5 -180 |
| -6 150 | 6 -150 |
| -9 100 | 9 -100 |
| -10 90 | 10 -90 |
| -12 75 | 12 -75 |
| -15 60 | 15 -60 |
| -18 50 | 18 -50 |
| -20 45 | 20 -45 |
| -25 36 | 25 -36 |
| -30 30 | 30 -30 |
Step 6: Find out which factor pair sums up to $\color{blue}{ b = 196 }$
Step 7: Because none of these pairs will give us a sum of $ \color{blue}{ 196 }$, we conclude the polynomial cannot be factored.