Question
$$x\cdot5-4x\cdot4+x\cdot3+10x\cdot2-4x-8 = 0$$
Answer
$$ x = 1 $$
Explanation
$$ \begin{aligned} x\cdot5-4x\cdot4+x\cdot3+10x\cdot2-4x-8 &= 0&& \text{simplify left side} \\[1 em]5x-16x+3x+20x-4x-8 &= 0&& \\[1 em]8x-8 &= 0&& \text{ move the constants to the right } \\[1 em]8x &= 8&& \text{ divide both sides by $ 8 $ } \\[1 em]x &= \frac{8}{8}&& \\[1 em]x &= 1&& \\[1 em] \end{aligned} $$
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