Question
$$x\cdot3-10x\cdot2-23x-14 = 0$$
Answer
$$ x = -\dfrac{7}{20} $$
Explanation
$$ \begin{aligned} x\cdot3-10x\cdot2-23x-14 &= 0&& \text{simplify left side} \\[1 em]3x-20x-23x-14 &= 0&& \\[1 em]-40x-14 &= 0&& \text{ move the constants to the right } \\[1 em]-40x &= 14&& \text{ divide both sides by $ -40 $ } \\[1 em]x &= -\frac{14}{40}&& \\[1 em]x &= -\frac{7}{20}&& \\[1 em] \end{aligned} $$
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