Question
$$x^2-\frac{33}{4}x+2 = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 4 } & x_2 = 8 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} x^2-\frac{33}{4}x+2 &= 0&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4x^2-4 \cdot \frac{33}{4}x+4\cdot2 &= 4\cdot0&& \text{cancel out the denominators} \\[1 em]4x^2-33x+8 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-33x+8 = 0 $ is a quadratic equation.
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