Question
$$v^2+2v-3 = 5$$
Answer
$$ \begin{matrix}v_1 = 2 & v_2 = -4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} v^2+2v-3 &= 5&& \text{move all terms to the left hand side } \\[1 em]v^2+2v-3-5 &= 0&& \text{simplify left side} \\[1 em]v^2+2v-8 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+2x-8 = 0 $ is a quadratic equation.
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