Question
$$9(x-5)^2+4 = 0$$
Answer
$$ \begin{matrix}x_1 = 5+\dfrac{ 2 }{ 3 }i & x_2 = 5-\dfrac{ 2 }{ 3 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 9(x-5)^2+4 &= 0&& \text{simplify left side} \\[1 em]9(x^2-10x+25)+4 &= 0&& \\[1 em]9x^2-90x+225+4 &= 0&& \\[1 em]9x^2-90x+229 &= 0&& \\[1 em] \end{aligned} $$
$ 9x^{2}-90x+229 = 0 $ is a quadratic equation.
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