Question
$$8+62x\cdot4 = 0$$
Answer
$$ x = -\dfrac{1}{6} $$
Explanation
$$ \begin{aligned} 8+62x\cdot4 &= 0&& \text{simplify left side} \\[1 em]8+6\cdot8x &= 0&& \\[1 em]8+48x &= 0&& \\[1 em]48x+8 &= 0&& \text{ move the constants to the right } \\[1 em]48x &= -8&& \text{ divide both sides by $ 48 $ } \\[1 em]x &= -\frac{8}{48}&& \\[1 em]x &= -\frac{1}{6}&& \\[1 em] \end{aligned} $$
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