Question
$$7a+8a^2+7a^0-4a^2-9a = 0$$
Answer
$$ \begin{matrix}a_1 = \dfrac{ 1 }{ 4 }+\dfrac{ 3 \sqrt{ 3}}{ 4 }i & a_2 = \dfrac{ 1 }{ 4 }-\dfrac{ 3 \sqrt{ 3}}{ 4 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 7a+8a^2+7a^0-4a^2-9a &= 0&& \text{simplify left side} \\[1 em]7a+8a^2+7a^0-4a^2-9a &= 0&& \\[1 em]4a^2-2a+7 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-2x+7 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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