Question
$$4x^2+\frac{9}{4}x-5 = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 9 }{ 32 }-\dfrac{\sqrt{ 1361 }}{ 32 } & x_2 = -\dfrac{ 9 }{ 32 }+\dfrac{\sqrt{ 1361 }}{ 32 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 4x^2+\frac{9}{4}x-5 &= 0&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4\cdot4x^2+4 \cdot \frac{9}{4}x-4\cdot5 &= 4\cdot0&& \text{cancel out the denominators} \\[1 em]16x^2+9x-20 &= 0&& \\[1 em] \end{aligned} $$
$ 16x^{2}+9x-20 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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