Question
$$4^2x\cdot3-4+6 = 0$$
Answer
$$ x = -\dfrac{1}{24} $$
Explanation
$$ \begin{aligned} 4^2x\cdot3-4+6 &= 0&& \text{simplify left side} \\[1 em]16x\cdot3-4+6 &= 0&& \\[1 em]48x-4+6 &= 0&& \\[1 em]48x+2 &= 0&& \text{ move the constants to the right } \\[1 em]48x &= -2&& \text{ divide both sides by $ 48 $ } \\[1 em]x &= -\frac{2}{48}&& \\[1 em]x &= -\frac{1}{24}&& \\[1 em] \end{aligned} $$
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