Question
$$3x\cdot3^2+2+4 = 0$$
Answer
$$ x = -\dfrac{2}{9} $$
Explanation
$$ \begin{aligned} 3x\cdot3^2+2+4 &= 0&& \text{simplify left side} \\[1 em]3x\cdot9+2+4 &= 0&& \\[1 em]27x+2+4 &= 0&& \\[1 em]27x+6 &= 0&& \text{ move the constants to the right } \\[1 em]27x &= -6&& \text{ divide both sides by $ 27 $ } \\[1 em]x &= -\frac{6}{27}&& \\[1 em]x &= -\frac{2}{9}&& \\[1 em] \end{aligned} $$
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