Question
$$2y^2-15y-4y+30 = 0$$
Answer
$$ \begin{matrix}y_1 = 2 & y_2 = \dfrac{ 15 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2y^2-15y-4y+30 &= 0&& \text{simplify left side} \\[1 em]2y^2-19y+30 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}-19x+30 = 0 $ is a quadratic equation.
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