Question
$$25x^3 = 64x$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = \dfrac{ 8 }{ 5 } & x_3 = -\dfrac{ 8 }{ 5 } \end{matrix} $$
Explanation
$$ \begin{aligned} 25x^3 &= 64x&& \text{move all terms to the left hand side } \\[1 em]25x^3-64x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 25x^{3}-64x = 0 } $, first we need to factor our $ x $.
$$ 25x^{3}-64x = x \left( 25x^{2}-64 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 25x^{2}-64 = 0$.
$ 25x^{2}-64 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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