Question
$$2(x+2)\cdot3(x-4) = 0$$
Answer
$$ \begin{matrix}x_1 = -2 & x_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2(x+2)\cdot3(x-4) &= 0&& \text{simplify left side} \\[1 em](2x+4)\cdot3(x-4) &= 0&& \\[1 em](6x+12)(x-4) &= 0&& \\[1 em]6x^2-24x+12x-48 &= 0&& \\[1 em]6x^2-12x-48 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}-12x-48 = 0 $ is a quadratic equation.
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