Question
$$-20x^3+33x^2-13x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 1 & x_3 = \dfrac{ 13 }{ 20 } \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ -20x^{3}+33x^{2}-13x = 0 } $, first we need to factor our $ x $.
$$ -20x^{3}+33x^{2}-13x = x \left( -20x^{2}+33x-13 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ -20x^{2}+33x-13 = 0$.
$ -20x^{2}+33x-13 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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