Question
$$(x+1)^2 = 6$$
Answer
$$ \begin{matrix}x_1 = -1-\sqrt{ 6 } & x_2 = -1+\sqrt{ 6 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+1)^2 &= 6&& \text{simplify left side} \\[1 em]x^2+2x+1 &= 6&& \text{move all terms to the left hand side } \\[1 em]x^2+2x+1-6 &= 0&& \text{simplify left side} \\[1 em]x^2+2x-5 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+2x-5 = 0 $ is a quadratic equation.
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