Question
$$(x-7)^2+3 = 0$$
Answer
$$ \begin{matrix}x_1 = 7+\sqrt{ 3 }i & x_2 = 7-\sqrt{ 3 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-7)^2+3 &= 0&& \text{simplify left side} \\[1 em]x^2-14x+49+3 &= 0&& \\[1 em]x^2-14x+52 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-14x+52 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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