Question
$$(x-5)^2 = 42$$
Answer
$$ \begin{matrix}x_1 = 5-\sqrt{ 42 } & x_2 = 5+\sqrt{ 42 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-5)^2 &= 42&& \text{simplify left side} \\[1 em]x^2-10x+25 &= 42&& \text{move all terms to the left hand side } \\[1 em]x^2-10x+25-42 &= 0&& \text{simplify left side} \\[1 em]x^2-10x-17 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-10x-17 = 0 $ is a quadratic equation.
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