Question
$$(x-5)^2 = 32$$
Answer
$$ \begin{matrix}x_1 = 5-4 \sqrt{ 2 } & x_2 = 5+4 \sqrt{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-5)^2 &= 32&& \text{simplify left side} \\[1 em]x^2-10x+25 &= 32&& \text{move all terms to the left hand side } \\[1 em]x^2-10x+25-32 &= 0&& \text{simplify left side} \\[1 em]x^2-10x-7 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-10x-7 = 0 $ is a quadratic equation.
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