Question
$$(x-3)^2 = 15$$
Answer
$$ \begin{matrix}x_1 = 3-\sqrt{ 15 } & x_2 = 3+\sqrt{ 15 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-3)^2 &= 15&& \text{simplify left side} \\[1 em]x^2-6x+9 &= 15&& \text{move all terms to the left hand side } \\[1 em]x^2-6x+9-15 &= 0&& \text{simplify left side} \\[1 em]x^2-6x-6 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-6x-6 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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