Question
$$(6x+2)(2x+8) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 3 } & x_2 = -4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (6x+2)(2x+8) &= 0&& \text{simplify left side} \\[1 em]12x^2+48x+4x+16 &= 0&& \\[1 em]12x^2+52x+16 &= 0&& \\[1 em] \end{aligned} $$
$ 12x^{2}+52x+16 = 0 $ is a quadratic equation.
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