Question
$$(6x-7)(4x+7) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 7 }{ 4 } & x_2 = \dfrac{ 7 }{ 6 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (6x-7)(4x+7) &= 0&& \text{simplify left side} \\[1 em]24x^2+42x-28x-49 &= 0&& \\[1 em]24x^2+14x-49 &= 0&& \\[1 em] \end{aligned} $$
$ 24x^{2}+14x-49 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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