Question
$$(6-x)\cdot(6-x) = 0$$
Answer
$$ x = 6 $$
Explanation
$$ \begin{aligned} (6-x)\cdot(6-x) &= 0&& \text{simplify left side} \\[1 em]36-6x-6x+x^2 &= 0&& \\[1 em]x^2-12x+36 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-12x+36 = 0 $ is a quadratic equation.
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