Question
$$(5x-7)(8x\cdot2+5x+11) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 7 }{ 5 } & x_2 = -\dfrac{ 11 }{ 21 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (5x-7)(8x\cdot2+5x+11) &= 0&& \text{simplify left side} \\[1 em](5x-7)(16x+5x+11) &= 0&& \\[1 em](5x-7)(21x+11) &= 0&& \\[1 em]105x^2+55x-147x-77 &= 0&& \\[1 em]105x^2-92x-77 &= 0&& \\[1 em] \end{aligned} $$
$ 105x^{2}-92x-77 = 0 $ is a quadratic equation.
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