Question
$$(4x-4)(-x+3) = 0$$
Answer
$$ \begin{matrix}x_1 = 1 & x_2 = 3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4x-4)(-x+3) &= 0&& \text{simplify left side} \\[1 em]-4x^2+12x+4x-12 &= 0&& \\[1 em]-4x^2+16x-12 &= 0&& \\[1 em] \end{aligned} $$
$ -4x^{2}+16x-12 = 0 $ is a quadratic equation.
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