Question
$$(3x+1)^2+2(3x+1)-4 = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 2 }{ 3 }-\dfrac{\sqrt{ 5 }}{ 3 } & x_2 = -\dfrac{ 2 }{ 3 }+\dfrac{\sqrt{ 5 }}{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3x+1)^2+2(3x+1)-4 &= 0&& \text{simplify left side} \\[1 em]9x^2+6x+1+2(3x+1)-4 &= 0&& \\[1 em]9x^2+6x+1+6x+2-4 &= 0&& \\[1 em]9x^2+12x+3-4 &= 0&& \\[1 em]9x^2+12x-1 &= 0&& \\[1 em] \end{aligned} $$
$ 9x^{2}+12x-1 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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