Question
$$3e^2-5e+7 = 6e+1$$
Answer
$$ \begin{matrix}e_1 = \dfrac{ 2 }{ 3 } & e_2 = 3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3e^2-5e+7 &= 6e+1&& \text{move all terms to the left hand side } \\[1 em]3e^2-5e+7-6e-1 &= 0&& \text{simplify left side} \\[1 em]3e^2-11e+6 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-11x+6 = 0 $ is a quadratic equation.
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