Question
$$(2x+3)^2-4x^2 = 10$$
Answer
$$ x = \dfrac{1}{12} $$
Explanation
$$ \begin{aligned} (2x+3)^2-4x^2 &= 10&& \text{simplify left side} \\[1 em]4x^2+12x+9-4x^2 &= 10&& \\[1 em]4x^2+12x+9-4x^2 &= 10&& \\[1 em]12x+9 &= 10&& \text{ move 9 to the right } \\[1 em]12x &= 10-9&& \\[1 em]12x &= 1&& \text{ divide both sides by $ 12 $ } \\[1 em]x &= \frac{1}{12}&& \\[1 em] \end{aligned} $$
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