In order to solve $ \color{blue}{ 2x^{5}-4x^{3} = 0 } $, first we need to factor our $ x^3 $.
$$ 2x^{5}-4x^{3} = x^3 \left( 2x^{2}-4 \right) $$$ x = 0 $ is a root of multiplicity $ 3 $.
The remaining roots can be found by solving equation $ 2x^{2}-4 = 0$.
$ 2x^{2}-4 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.