Question
$$2x^2+3x-1-(3x^2+2x+5) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 23 }}{ 2 }i & x_2 = \dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 23 }}{ 2 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2x^2+3x-1-(3x^2+2x+5) &= 0&& \text{simplify left side} \\[1 em]2x^2+3x-1-3x^2-2x-5 &= 0&& \\[1 em]-x^2+x-6 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}+x-6 = 0 $ is a quadratic equation.
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