Question
$$(2n+2)(6n+1) = 0$$
Answer
$$ \begin{matrix}n_1 = -1 & n_2 = -\dfrac{ 1 }{ 6 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2n+2)(6n+1) &= 0&& \text{simplify left side} \\[1 em]12n^2+2n+12n+2 &= 0&& \\[1 em]12n^2+14n+2 &= 0&& \\[1 em] \end{aligned} $$
$ 12x^{2}+14x+2 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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