Question
$$(2b-4)(3b+4) = 0$$
Answer
$$ \begin{matrix}b_1 = 2 & b_2 = -\dfrac{ 4 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2b-4)(3b+4) &= 0&& \text{simplify left side} \\[1 em]6b^2+8b-12b-16 &= 0&& \\[1 em]6b^2-4b-16 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}-4x-16 = 0 $ is a quadratic equation.
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