$$ \begin{aligned} -8x+10-(3x\cdot2-x+6) &= 0&& \text{simplify left side} \\[1 em]-8x+10-(6x-x+6) &= 0&& \\[1 em]-8x+10-(5x+6) &= 0&& \\[1 em]-8x+10-5x-6 &= 0&& \\[1 em]-13x+4 &= 0&& \text{ move the constants to the right } \\[1 em]-13x &= -4&& \text{ divide both sides by $ -13 $ } \\[1 em]x &= \frac{-4}{-13}&& \\[1 em]x &= \frac{4}{13}&& \\[1 em] \end{aligned} $$

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