Question
$$(-10x+4)\cdot(3-8x) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 2 }{ 5 } & x_2 = \dfrac{ 3 }{ 8 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (-10x+4)\cdot(3-8x) &= 0&& \text{simplify left side} \\[1 em]-30x+80x^2+12-32x &= 0&& \\[1 em]80x^2-62x+12 &= 0&& \\[1 em] \end{aligned} $$
$ 80x^{2}-62x+12 = 0 $ is a quadratic equation.
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