Question
What is the quotient and remainder when $ 1431 $ is divided by $ 27 $ ?
Answer
The quotient is 53 and the remainder is 0.
Explanation
| Division Table | |||||
| 0 | 0 | 5 | 3 | ||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | 3 | |||
| – | 1 | 3 | 5 | ||
| 8 | 1 | ||||
| – | 8 | 1 | |||
| 0 | |||||
|
STEP 0: set up a division table |
|||||
| 2 | 7 | 1 | 4 | 3 | 1 |
|
STEP 1: DIVIDE 1 : 27 = 0 with a remainder of 1 |
|||||
| 0 | |||||
| 2 | 7 | 1 | 4 | 3 | 1 |
|
STEP 2: MULTIPLY 0 · 27 = 0 |
|||||
| 0 | |||||
| 2 | 7 | 1 | 4 | 3 | 1 |
| 0 | |||||
|
STEP 3: SUBTRACT 1 - 0 = 1 |
|||||
| 0 | |||||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | |||||
| STEP 4: BRING DOWN | |||||
| 0 | |||||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
|
STEP 5: DIVIDE 14 : 27 = 0 with a remainder of 14 |
|||||
| 0 | 0 | ||||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
|
STEP 6: MULTIPLY 0 · 27 = 0 |
|||||
| 0 | 0 | ||||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| 0 | |||||
|
STEP 7: SUBTRACT 14 - 0 = 14 |
|||||
| 0 | 0 | ||||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | ||||
| STEP 8: BRING DOWN | |||||
| 0 | 0 | ||||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | 3 | |||
|
STEP 9: DIVIDE 143 : 27 = 5 with a remainder of 8 |
|||||
| 0 | 0 | 5 | |||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | 3 | |||
|
STEP 10: MULTIPLY 5 · 27 = 135 |
|||||
| 0 | 0 | 5 | |||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | 3 | |||
| 1 | 3 | 5 | |||
|
STEP 11: SUBTRACT 143 - 135 = 8 |
|||||
| 0 | 0 | 5 | |||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | 3 | |||
| – | 1 | 3 | 5 | ||
| 8 | |||||
| STEP 12: BRING DOWN | |||||
| 0 | 0 | 5 | |||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | 3 | |||
| – | 1 | 3 | 5 | ||
| 8 | 1 | ||||
|
STEP 13: DIVIDE 81 : 27 = 3 with a remainder of 0 |
|||||
| 0 | 0 | 5 | 3 | ||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | 3 | |||
| – | 1 | 3 | 5 | ||
| 8 | 1 | ||||
|
STEP 14: MULTIPLY 3 · 27 = 81 |
|||||
| 0 | 0 | 5 | 3 | ||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | 3 | |||
| – | 1 | 3 | 5 | ||
| 8 | 1 | ||||
| 8 | 1 | ||||
|
STEP 15: SUBTRACT 81 - 81 = 0 |
|||||
| 0 | 0 | 5 | 3 | ||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | 3 | |||
| – | 1 | 3 | 5 | ||
| 8 | 1 | ||||
| – | 8 | 1 | |||
| 0 | |||||
|
STEP 15: SUBTRACT 81 - 81 = 0 |
|||||
| 0 | 0 | 5 | 3 | ||
| 2 | 7 | 1 | 4 | 3 | 1 |
| – | 0 | ||||
| 1 | 4 | ||||
| – | 0 | ||||
| 1 | 4 | 3 | |||
| – | 1 | 3 | 5 | ||
| 8 | 1 | ||||
| – | 8 | 1 | |||
| 0 | |||||
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