The distance between the line and the point is:
$$ d = 5 $$The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:
$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$After substituting: $ A = 20 $ , $ B = -21 $ , $ C = -42 $ , $ x_0 = -2 $ and $ y_0 = 3 $ we have:
$$ \begin{aligned} d =& \frac{ \left| 20\cdot\left(-2\right) +\left(-21\right)\cdot3 + \left( -42\right) \right| }{\sqrt{ 20^2 + (-21)^2}} = \\ d =& \frac{ \left| -40 -63 -42 \right| }{\sqrt{ 400 + 441}} = \\ d =& \frac{ \left| -145 \right| }{\sqrt{ 841}} = \\ d =& \frac{ 145 }{ 29 } = \\ d =& 5 \end{aligned} $$