The distance between the line and the point is:
$$ d = \frac{ 23 \sqrt{ 74}}{ 74 } $$The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:
$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$After substituting: $ A = 7 $ , $ B = -5 $ , $ C = -11 $ , $ x_0 = 7 $ and $ y_0 = 3 $ we have:
$$ \begin{aligned} d =& \frac{ \left| 7\cdot7 +\left(-5\right)\cdot3 + \left( -11\right) \right| }{\sqrt{ 7^2 + (-5)^2}} = \\ d =& \frac{ \left| 49 -15 -11 \right| }{\sqrt{ 49 + 25}} = \\ d =& \frac{ \left| 23 \right| }{\sqrt{ 74}} = \\ d =& \frac{ 23 }{ \sqrt{ 74 } } = \\ d =& \frac{ 23 \sqrt{ 74}}{ 74 } \end{aligned} $$