The distance between the line and the point is:
$$ d = \frac{ 3 }{ 5 } $$The distance from the point $ (x_0, y_0) $ to the line $ Ax + By + C = 0 $ is given by:
$$ d = \frac{ \left| Ax_0 + B_yo + C \right| }{ \sqrt{A^2 + B^2}} $$After substituting: $ A = 3 $ , $ B = -4 $ , $ C = -26 $ , $ x_0 = 3 $ and $ y_0 = -5 $ we have:
$$ \begin{aligned} d =& \frac{ \left| 3\cdot3 +\left(-4\right)\cdot\left(-5\right) + \left( -26\right) \right| }{\sqrt{ 3^2 + (-4)^2}} = \\ d =& \frac{ \left| 9 + 20 -26 \right| }{\sqrt{ 9 + 16}} = \\ d =& \frac{ \left| 3 \right| }{\sqrt{ 25}} = \\ d =& \frac{ 3 }{ 5 } = \\ d =& \frac{ 3 }{ 5 } \end{aligned} $$